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If a 12 volt battery is connected to a series circuit with three resistors of 2 ohms, 4 ohms, and 6 ohms, how much current will flow through the circuit?

  1. 1 ampere

  2. 2 amperes

  3. 3 amperes

  4. 4 amperes

The correct answer is: 1 ampere

To find the amount of current flowing through the circuit, first, it's essential to determine the total resistance of the series circuit. In a series circuit, the total resistance is the sum of the resistances of all the components involved. In this case, the resistors have values of 2 ohms, 4 ohms, and 6 ohms. Therefore, the total resistance (R_total) can be calculated as follows: \[ R_{\text{total}} = R_1 + R_2 + R_3 = 2 \, \text{ohms} + 4 \, \text{ohms} + 6 \, \text{ohms} = 12 \, \text{ohms} \] Next, to find the current flowing through the circuit, Ohm's Law is applied, which states: \[ I = \frac{V}{R} \] Here, \( I \) represents the current in amperes, \( V \) is the voltage in volts, and \( R \) is the total resistance in ohms. Given that the battery provides 12 volts, we can substitute the known values into the equation: \[ I = \frac{12 \, \