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What is the value of the third resistor if two parallel resistors of 3 ohms and 6 ohms have a total current flow of 12 amperes?

  1. 1 Ω

  2. 2 Ω

  3. 3 Ω

  4. 4 Ω

The correct answer is: 2 Ω

To find the value of the third resistor when two parallel resistors of 3 ohms and 6 ohms are involved in a circuit with a total current flow of 12 amperes, we first need to understand how resistors behave in parallel. In a parallel circuit, the total resistance can be calculated using the formula for parallel resistors. The formula for total resistance (R_total) in parallel is given by: 1/R_total = 1/R1 + 1/R2 + 1/R3 For this case, the two resistors are 3 ohms and 6 ohms. We first calculate the resistance of these two: 1/R_total = 1/3 + 1/6. Finding a common denominator (which is 6): 1/R_total = (2 + 1) / 6 = 3/6 = 1/2. Thus, R_total for the 3 ohm and 6 ohm resistors is: R_total = 2 ohms. Now we know that the total resistance for the two resistors alone is 2 ohms, but the question mentions the total current flow is 12 amperes. We can use Ohm’s Law (V =